4(x-6)+3(8-x)=^2x-3

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Solution for 4(x-6)+3(8-x)=^2x-3 equation: 



4(x-6)+3(8-x)=^2x-3

We move all terms to the left:

4(x-6)+3(8-x)-(^2x-3)=0

We add all the numbers together, and all the variables

4(x-6)+3(-1x+8)-(^2x-3)=0

We multiply parentheses

4x-3x-(^2x-3)-24+24=0

We get rid of parentheses

4x-3x-^2x+3-24+24=0

We add all the numbers together, and all the variables

x-^2x+3=0

We move all terms containing x to the left, all other terms to the right

x-^2x=-3

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